A) \[-3.94\text{ }cm\]
B) 4.3 cm
C) \[-4.93cm\]
D) 3.94cm
Correct Answer: C
Solution :
Due to glass slab, increase in path \[=(\mu -1)t=(1.5-1)3cm=1.5\,cm\] \[\therefore\] \[\mu '=-(21+1.5)cm\] or \[\mu '=-22.5cm\] Now, \[\frac{1}{-22.5}+\frac{1}{v}=\frac{1}{-5}\] Or \[\frac{1}{v}=\frac{1}{22.5}-\frac{1}{5}\] Or \[\frac{1}{v}=\frac{5-22.5}{22.5\times 5}\] Or \[v=\frac{22.5\times 5}{17.5}cm\] or \[v=-\text{ }6.43\text{ }cm\] Geometrical distance \[=-(6.43-1.5)\text{ }cm\] \[=-\text{ }4.93\text{ }cm\]You need to login to perform this action.
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