A) \[2.4\times {{10}^{4}}\text{ }cal\]
B) \[6\times {{10}^{4}}\text{ }cal\]
C) \[1.2\times {{10}^{4}}cal\]
D) \[4.8\times {{10}^{4}}\text{ }cal\]
Correct Answer: C
Solution :
Efficiency, \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}=\frac{W}{Q}\] \[W=\frac{Q({{T}_{1}}-{{T}_{2}})}{{{T}_{2}}}\] \[=\frac{6\times {{10}^{4}}[(227+273)-(127+273)]}{(227+273)}\] \[=\frac{6\times {{10}^{4}}\times 100}{500}=1.2\times {{10}^{4}}cal\]You need to login to perform this action.
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