A) 0.282
B) 0.0796
C) 0.0199
D) 1.99
Correct Answer: C
Solution :
\[2HI{{H}_{2}}+{{I}_{2}}\] | |||
Initially | 2 | 0 | 0 |
at equilibrium | \[2-\frac{2\times 22}{100}\] | \[\frac{2\times 22}{100}\] | \[\frac{2\times 22}{100}\] |
= 2 - 0.44 | = 0.22 | = 0.22 | |
= 1.56 |
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