A) 0.5 A
B) 1 A
C) 1.5 A
D) 2 A
Correct Answer: B
Solution :
\[\frac{1}{2}C{{V}^{2}}=\frac{1}{2}L{{i}^{2}}\] \[\therefore \] \[{{10}^{-6}}\times {{(10)}^{2}}=0.1\times {{10}^{-3}}\times {{I}^{2}}\] \[{{10}^{-6}}\times 100=0.1\times {{10}^{-3}}\times {{I}^{2}}\] \[{{I}^{2}}=\frac{100\times {{10}^{-6}}}{0.1\times {{10}^{-3}}}=1\]You need to login to perform this action.
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