A) \[_{94}P{{u}^{239}}\]
B) \[_{90}P{{u}^{219}}\]
C) \[_{93}P{{U}^{240}}\]
D) \[_{92}P{{U}^{240}}\]
Correct Answer: A
Solution :
The reaction can be shown as \[_{92}{{U}^{238}}{{+}_{0}}{{n}^{1}}{{\xrightarrow{{}}}_{92}}{{U}^{239}}\xrightarrow[{}]{{}}\] \[_{93}N{{e}^{239}}{{+}_{-1}}{{e}^{0}}{{\xrightarrow{{}}}_{-1}}{{e}^{0}}{{+}_{94}}P{{u}^{239}}\]You need to login to perform this action.
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