A) 0.4
B) 0.16
C) 2.5
D) 6.25
Correct Answer: B
Solution :
In Ingen Hausz experiment \[K\propto {{l}^{2}}\] \[\therefore \] \[\frac{{{K}_{Fe}}}{{{K}_{Ag}}}={{\left( \frac{{{l}_{Fe}}}{{{l}_{Ag}}} \right)}^{2}}\] \[\frac{{{K}_{Fe}}}{1}={{\left( \frac{2}{5} \right)}^{2}}\] \[{{K}_{Fe}}=\frac{4}{25}\] \[=0.16\]You need to login to perform this action.
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