A) \[\frac{F}{M}(\cos \phi +\mu \sin \phi )-\mu g\]
B) \[F\sin \frac{\phi }{M}\]
C) \[\mu F\cos \phi \]
D) \[\mu Fsin\,\phi \]
Correct Answer: A
Solution :
\[R=Mg-F\,\sin \phi \] \[f=\mu R=\mu =(Mg-F\sin \phi )\] \[F=\cos \phi -f=Ma\] \[a=\frac{1}{M}[F\cos \phi -f]\] \[a=\frac{1}{M}[F\cos \phi -\mu (Mg-F\sin \phi )]\] \[=\frac{F}{M}cos\phi -\mu g+\frac{\mu F}{M}\sin \phi \] \[=\frac{F}{M}[\cos \phi +\mu \sin \phi ]-\mu g\]You need to login to perform this action.
You will be redirected in
3 sec