A) \[{{P}_{2}}{{O}_{3}}<A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<S{{O}_{2}}\]
B) \[Si{{O}_{2}}<S{{O}_{2}}<A{{l}_{2}}{{O}_{3}}<{{P}_{2}}{{O}_{3}}\]
C) \[A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<{{P}_{2}}{{O}_{3}}<S{{O}_{2}}\]
D) \[S{{O}_{2}}<{{P}_{2}}{{O}_{3}}<Si{{O}_{2}}<A{{l}_{2}}{{O}_{3}}\]
Correct Answer: C
Solution :
With decrease in size from\[Al\]to S, the basic nature of oxide decrease and acidic nature increases. Hence, the order of acid strength is as \[A{{l}_{2}}{{O}_{3}}<Si{{O}_{2}}<{{P}_{2}}{{O}_{3}}<S{{O}_{2}}\]You need to login to perform this action.
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