A) \[s{{p}^{3}}\]
B) \[{{d}^{2}}s{{p}^{3}}\]
C) \[s{{p}^{3}}{{d}^{2}}\]
D) \[ds{{p}^{3}}\]
Correct Answer: B
Solution :
\[F{{e}^{3+}}:[Ar]3{{d}^{5}}\] Number of ligand = 6 Nature of ligand is strong field. \[F{{e}^{3+}}:\] \[{{[Fe{{(CN)}_{6}}]}^{3-}}:\] Hence, hybridization of Fe is\[{{d}^{2}}s{{p}^{3}}\].You need to login to perform this action.
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