A) 0.3 N
B) 0.6 N
C) 2.4 N
D) 1.2 N
Correct Answer: A
Solution :
Force between two magnets is given by \[F=\frac{{{\mu }_{\,0}}}{4\,\pi }\left( \frac{6\,{{M}_{1}}\,{{M}_{2}}}{{{r}^{4}}} \right)\] \[\Rightarrow \] \[F\propto \frac{1}{{{r}^{4}}}\] \[\therefore \] \[\frac{{{F}_{1}}}{{{F}_{2}}}={{\left( \frac{{{r}_{2}}}{{{r}_{1}}} \right)}^{4}}\] \[\frac{4.8}{{{F}_{2}}}={{\left( \frac{2r}{r} \right)}^{4}}=16\] \[\Rightarrow \] \[{{F}_{2}}=0.3\,N\]You need to login to perform this action.
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