A) 1
B) 2
C) 1/4
D) 4
Correct Answer: D
Solution :
Given, molecular mass of gas B = 1 \[\therefore \]vapour density of gas\[B=\frac{1}{2}\] \[\because \]vapour density of A is 4 times of B \[\therefore \]vapour density of\[A=\frac{1}{2}\times 4=2\] \[\therefore \]molecular mass of\[A=2\times 2=4\]. (\[\because \]\[molecular\text{ }mass=2\times vapour\text{ }density\])You need to login to perform this action.
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