A) Butyne
B) Propyne
C) 2-pentyne
D) Ethyne
Correct Answer: B
Solution :
Propyne on oxidation with\[KMn{{O}_{4}}\]produces pyruvic acid. \[C{{H}_{3}}-C\equiv CH\xrightarrow[KMn{{O}_{4}}]{[O]}\underset{Pyruvic\text{ }acid}{\mathop{C{{H}_{3}}-\overset{\begin{smallmatrix} O \\ || \end{smallmatrix}}{\mathop{C}}\,-COOH}}\,\]You need to login to perform this action.
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