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BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    The energy of photon of light wavelength 450 nm is:                                                                    [BHU PMT-2002]

    A)                  \[1788\]                             

    B)                  \[1192\]

    C)                  \[596\]                

    D)                  \[298\]

    Correct Answer: C

    Solution :

                     The energy of a photon is given by                                 \[{{x}^{2}}\]                 Where, \[x\] is Planck?s constant and \[m\] is frequency of light.                 Also velocity =frequency (v)                 X wavelength (\[h\])]                 Where \[d\],                 \[mg\left( 1+\frac{h}{d} \right)\]                 \[mg{{\left( 1+\frac{h}{d} \right)}^{2}}\]               \[mg\left( 1-\frac{h}{d} \right)\]                                 \[mg\]


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