A) \[n\]
B) \[2\]
C) \[-2\]
D) \[+1\]
Correct Answer: C
Solution :
Kinetic energy of rotation is half the product of the moment of inertia \[{{\omega }_{1}}\] of the body and square of the angular velocity \[{{\omega }_{2}}\] of the body. \[{{\omega }_{2}}-{{\omega }_{1}}\] \[{{\omega }_{1}}:{{\omega }_{2}}\] Given, \[\sqrt{{{\omega }_{1}}}:\sqrt{{{\omega }_{2}}}\] \[\sqrt{{{\omega }_{2}}}:\sqrt{{{\omega }_{1}}}\] \[m\] \[a\] \[\mu \] \[g\left( \cos \,\,a-\mu \,\,\sin \,\,a \right)\] Also angular acceleration \[g\left( sin\,\,a-\mu \,\,\cos \,\,a \right)\]\[\mu \,\,\cos \,\,a\] time \[g\,\,\sin \,\,a\]=angular velocity\[Zero\] \[0.125\,\,kg\] \[0.5\,\,kg\].
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