A) \[{{A}_{1}},{{A}_{2}},{{A}_{3}}\]
B) \[A_{1}^{2}\omega _{1}^{2}=A_{2}^{2}\omega _{2}^{2}=A_{3}^{2}\omega _{3}^{2}\]
C) \[A_{1}^{2}{{\omega }_{1}}=A_{2}^{2}{{\omega }_{2}}=A_{3}^{2}{{\omega }_{3}}\]
D) \[{{A}_{1}}\omega _{1}^{2}={{A}_{2}}\omega _{2}^{2}={{A}_{3}}\omega _{3}^{2}\]
Correct Answer: C
Solution :
Magnetic field at the center of a circular coil carrying current \[335\,\,m/s\] and of radius \[6\], having \[5\] number of turns is \[3\] \[4\] Given,\[4\mu m\] \[1\,m\] Note: Direction of magnetic field is perpendicular to the plane of the coil that is along the axis of the coil.
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