BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    The angular velocities of three bodies in simple harmonic motion are \[70\,N/m\] with their respective amplitudes as\[2700\,\,{{m}^{3}}\]. If all the three bodies have same mass and velocity, then:           [BHU PMT-2002]

    A) \[1900\,\,{{m}^{3}}\]

    B) \[1700\,\,{{m}^{3}}\]    

    C) \[1500\,\,{{m}^{3}}\]

    D) \[{{v}_{0  }}\]

    Correct Answer: D

    Solution :

                     Key Idea: Rate of change of displacement is known as velocity.                 The equation for displacement \[\overset{\to }{\mathop{b}}\,\times \overset{\to }{\mathop{a}}\,\] of a body in SHM with angular velocity \[\overset{\to }{\mathop{a}}\,\times \overset{\to }{\mathop{b}}\,\] is given by                 \[n\]                 Where a is amplitude.                 Velocity is \[2\]rate of change of displacement \[-2\]                 \[+1\] \[-1\]                 Given, \[5\times {{10}^{-5}}\,T\]                 \[3\times {{10}^{-5}}\,T\]                             \[1.25\times {{10}^{-4}}\,T\]                 \[0.5\times {{10}^{-5}}\,T\]                         \[{{v}_{d}}\]


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