BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    If the value of surface tension of a liquid is\[\mu \], then its value in \[\frac{v_{0}^{2}}{\mu }\] will be: [BHU PMT-2002]

    A)                  \[{{\left( \frac{{{v}_{0}}}{{{\mu }_{g}}} \right)}^{2}}\]                    

    B)                  \[\frac{v_{0}^{2}}{{{\mu }_{g}}}\]

    C)                  \[\frac{v_{0}^{2}}{2{{\mu }_{g}}}\]                        

    D)                  \[{{v}_{1}}\]

    Correct Answer: C

    Solution :

                     Key Idea: The unit dynes/cm is CGS system of unit.                 The CGS unit of force is dyne and SI unit is Newton. Also there are \[i\] dynes in one Newton and 100 cm in 1 m.                 \[\frac{{{v}_{d}}}{8}\]


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