A) \[{{C}_{p}}\left( {{T}_{1}}-{{T}_{2}} \right)\]
B) \[{{C}_{V}}\left( {{T}_{1}}-{{T}_{2}} \right)\]
C) \[R\left( {{T}_{1}}-{{T}_{2}} \right)\]
D) \[Zero\]
Correct Answer: A
Solution :
Key Idea : Volume of wire remains constant after stretching. The resistance of a wire of length\[\frac{l}{2}\], area of cross-section A, specific resistance p is given by \[n'=\frac{v}{4\left( \frac{l}{2} \right)}=\frac{v}{2l}=n=\] Also volume=length\[{{V}_{i}}\] area =\[{{V}_{f}}\]=constant. Or \[W=\int_{{{V}_{i}}}^{{{V}_{f}}}{PdV}\] \[P\] And \[\mathbf{dV}\] \[P{{V}^{\gamma }}=K\] \[\therefore \]
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