BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    A car travelling on a straight track moves with uniform velocity of \[1.0\,\,eV\] for some time and with uniform velocity \[\overset{\circ }{\mathop{\text{A}}}\,\] for the next equal time the average velocity of the car is:            [BHU PMT-2002]

    A)                  \[\overset{\circ }{\mathop{\text{A}}}\,\]                                           

    B)                  \[0.\text{6}~\text{mm}\]

    C)                  \[0.\text{5 mm}~\]                                       

    D)                  \[0.4\text{5 mm}~\]

    Correct Answer: C

    Solution :

                     Key Idea: Average velocity is equal to ratio of total displacement to total time.                 Velocity is a water quantity and average velocity is defined as the total displacement undergone by the body per unit time.                 Displacement in first instance= \[{{v}_{0 & }}\]                 Displacement in second instance= \[\mu \]                 \[\frac{v_{0}^{2}}{\mu }\]Average velocity= \[{{\left( \frac{{{v}_{0}}}{{{\mu }_{g}}} \right)}^{2}}\]


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