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BHU PMT BHU PMT Solved Paper-2002

  • question_answer
    0.2595 g of an organic compound in a quantitative analysis yielded 0.35 g of the barium sulphate. The percentage of sulphur in the compound is:

    A)  48.76                                   

    B)  36.62

    C)  24.45                                   

    D)  18.52

    Correct Answer: D

    Solution :

                     Key Idea: by the use of following formula we can find the percentage of sulphur in the organic compound: % of\[S=\frac{32}{233}\times \frac{mass\text{ }of\text{ }BaS{{O}_{4}}\text{ }formed}{mass\text{ }of\text{ }organic\text{ }comp.}\times 100\]                 \[=\frac{32}{233}\times \frac{0.35}{0.2595}\times 100\] \[=18.52%\]


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