A) \[n=2,l=1,m=0,s=0\]
B) \[n=2,,l=-2,m=1,s=+\frac{1}{2}\]
C) \[n=2,,l=2,m=-1,s=-\frac{1}{2}\]
D) \[n=2,,l=1,m=0,s=+\frac{1}{2}\]
Correct Answer: D
Solution :
Key Idea: The possible sets of quantum numbers are as follows: \[n=0\]to \[\infty \] \[l=from\text{ }0\text{ }to\text{ }n-1\] \[m=from-I\text{ }to\text{ }zero\text{ }to+l\] \[s=\frac{1}{2}\]and \[-\frac{1}{2}\] By comparing the given data with these we can find which correct set of quantum numbers is. \[n=2,l=1,\text{ }m=0,\text{ }s=0\] \[\because \]s cannot have value of 0 \[\therefore \]it is not correct. \[n=2,l=-2,m=-1,s=+\frac{1}{2}\] \[\because \]I cannot have negative value \[\therefore \]this set of quantum number is not correct \[n=2,l=2,\text{ }m=-1,s=-\frac{1}{2}\] \[\because \]the value or I is always from 0 to n\[-1\] \[\therefore \]this set of quantum number is not correct. \[n=2,l=1,\text{ }m=0,s=+\frac{1}{2}\] \[\because \]All the numbers in accordance with rule \[\therefore \]This set of quantum numbers is possible
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