A) methyl alcohol and phenyl ether
B) methyl iodide and phenol
C) methyl iodide and phenyl iodide
D) benzyl alcohol and methane
Correct Answer: B
Solution :
Key Idea: Steric hinderance. Due to steric hinderance of larger alkyl group the halide ion attacks the smaller alkyl group. \[\therefore \]Phenol and alkyl halide having smaller alkyl group is formed.You need to login to perform this action.
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