question_answer

Methyl phenyl ether on heating with HI produce:

A)  methyl alcohol and phenyl ether

B)  methyl iodide and phenol

C)  methyl iodide and phenyl iodide

D)  benzyl alcohol and methane

Correct Answer: B

Solution :

                 Key Idea: Steric hinderance. Due to steric hinderance of larger alkyl group the halide ion attacks the smaller alkyl group. \[\therefore \]Phenol and alkyl halide having smaller alkyl group is formed.