A) \[\text{9 }%\]
B) \[\text{9}\text{.3}\times \text{1}{{\text{0}}^{-11}}\text{ }%\]
C) \[\text{10 }%\]
D) \[\text{None of these}\]
Correct Answer: B
Solution :
From Einstein?s mass energy relation \[E=\Delta \,m\,\,{{c}^{2}}\] ?(1) Where \[\Delta \,m\] is mass lost, c is speed of light. Also heat given by body is \[E=mc\Delta 0\] ?(2) Where, c is specific heat, Equating Eqs. (1) and (2), we get \[\Delta m=\frac{mc\Delta \theta }{{{c}^{2}}}=\frac{m\times 0.2\times 100\times 4.2\times {{10}^{3}}\,J}{{{\left( 3\times {{10}^{8}} \right)}^{2}}}\] \[\Rightarrow \] \[\frac{\Delta m}{m}=\frac{20\times 4.2\times {{10}^{3}}}{{{\left( 3\times {{10}^{8}} \right)}^{2}}}\] % increase in mass \[\frac{\Delta m}{m}=100\] \[=\frac{20\times 4.2\times {{10}^{3}}}{{{\left( 3\times {{10}^{8}} \right)}^{2}}}\times 100\] \[=9.3\times {{10}^{-11}}\,%\]
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