A) \[\overset{\to }{\mathop{M\times }}\,\overset{\to }{\mathop{B}}\,\]
B) \[\overset{\to }{\mathop{M-}}\,\overset{\to }{\mathop{B}}\,\]
C) \[\frac{1}{2}\overset{\to }{\mathop{M\times }}\,\overset{\to }{\mathop{B}}\,\]
D) \[\overset{\to }{\mathop{M+}}\,\overset{\to }{\mathop{B}}\,\]
Correct Answer: A
Solution :
Key Idea: Torque is equal to instantaneous moment of deflecting couple. The torque acting is given by \[\tau =force\left( {{F}_{1}}={{F}_{2}} \right)\times \]perpendicular distance \[\tau =i\,\,B\,\,l\times b\,\,\sin \,\,\theta \] Where \[i\] is current, \[B\] is magnetic field, \[l\] the length and \[b\] the distance. The term \[ilb=\overset{\to }{\mathop{M}}\,=\]dipole moment \[\therefore \] \[\overset{\to }{\mathop{\tau }}\,=\overset{\to }{\mathop{M}}\,\overset{\to }{\mathop{B}}\,\,\sin \,\theta \] \[\overset{\to }{\mathop{\tau }}\,=\overset{\to }{\mathop{M}}\,\times \overset{\to }{\mathop{B}}\,\]You need to login to perform this action.
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