A) \[H{{g}^{2+}}/dil.\,{{H}_{2}}S{{O}_{4}}\]
B) \[KMn{{O}_{4}}\]
C) \[KCl{{O}_{3}}\]
D) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\]
Correct Answer: A
Solution :
Alkyne forms carbonyl compounds on hydrolysis in presence of mercury salt. \[C{{H}_{3}}C{{H}_{2}}C\equiv CH\xrightarrow[H{{g}^{2+}}/{{H}_{2}}S{{O}_{4}}]{HOH}\underset{bu\tan one-2}{\mathop{C{{H}_{3}}C{{h}_{2}}COC{{H}_{3}}}}\,\]
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