2. Solved Papers
  3. BHU PMT

BHU PMT BHU PMT Solved Paper-2003

  • question_answer
    \[\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{C{{H}_{2}}}}\,C{{H}_{3}}\xrightarrow{catalyst}C=\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,\] Number of optical isomer possible will be:

    A)  2     

    B)  4

    C)  0                                            

    D) 3

    Correct Answer: A

    Solution :

    \[C{{H}_{3}}-\overset{\begin{smallmatrix}  C{{H}_{2}}C{{H}_{3}} \\  | \end{smallmatrix}}{\mathop{C}}\,=\underset{\begin{smallmatrix}  | \\  C{{H}_{3}} \end{smallmatrix}}{\mathop{CH}}\,+{{H}_{2}}\xrightarrow[{}]{{}}C{{H}_{3}}-\underset{\begin{smallmatrix}  | \\  H \end{smallmatrix}}{\overset{\begin{smallmatrix}  C{{H}_{2}}C{{H}_{3}} \\  | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{2}}-C{{H}_{3}}\] \[\because \]This product is found in d and I form. \[\therefore \]Two optical isomers are possible.                                


You need to login to perform this action.
You will be redirected in 3 sec spinner