BHU PMT BHU PMT Solved Paper-2003

  • question_answer
    \[{{H}_{2}}{{C}_{2}}{{O}_{4}}+KMn{{O}_{4}}\]in acidic medium reacts to have change in oxidation number of Mn from:

    A)  7 to 5                                   

    B)  2 to 7

    C)  5 to 7                                   

    D)  7 to 2

    Correct Answer: D

    Solution :

                     \[2KMn{{O}_{4}}+5{{H}_{2}}{{C}_{2}}{{O}_{4}}+6HCl\xrightarrow{{}}2MnC{{l}_{2}}\] \[+10C{{O}_{2}}+8{{H}_{2}}O\] \[\therefore \]  \[MnO_{4}^{-}\xrightarrow[{}]{{}}M{{n}^{2+}}\] Oxidation state of Mn in\[MnO_{4}^{-}\] \[x+4{{x}^{-2}}=-1\] \[x+(-8)=-1\] \[x=7\] Oxidation state of Mn in\[M{{n}^{2+}}=2\] \[\therefore \]Change in oxidation state = 7 to 2


You need to login to perform this action.
You will be redirected in 3 sec spinner