A) \[3.6\times {{10}^{6}}\,\,N/C\]
B) \[1.8\times {{10}^{6}}\,\,N/C\]
C) \[Zero\]
D) \[0.9\times {{10}^{6}}\,\,N/C\]
Correct Answer: C
Solution :
Key Idea: The electric field inside Gaussian surface is zero. The Gaussian surface lying inside the sphere encloses no field. The field according to Gauss law, $\mathop{\oint }^{}E-ds\frac{Q}{{{\varepsilon }_{0}}}$ Will be, for $Q=0$ \[\mathop{\oint }^{}E-ds=0\] Hence, electric field is zero.
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