A) \[K=[Ar]4{{s}^{1}}\]
B) \[Cr=[Ar]3{{d}^{5}},4{{s}^{1}}\]
C) \[Cr=[Ar]3{{d}^{4}},4{{s}^{2}}\]
D) \[Cu=[Ar]3{{d}^{10}},4{{s}^{1}}\]
Correct Answer: C
Solution :
The configuration of K is correct. In d orbitals as exactly half filled and exactly full filled orbitals are more stable than nearly half filled and nearly full filled orbitals. Hence, in case of Cr and Cu one electron shirts from 4s orbital to 3d orbital to give them stable electronic configuration. So,\[Cr=[Ar]\,3{{d}^{4}},4{{s}^{2}}\]is incorrect configuration.
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