A) \[C{{H}_{3}}COOH\]
B) \[{{C}_{6}}{{H}_{5}}COOH\]
C) \[HCOOH\]
D) \[C{{H}_{3}}C{{H}_{2}}COOH\]
Correct Answer: B
Solution :
Key Idea:\[{{H}^{+}}\]donors are acids. Electron donating groups increase acidity and electron withdrawing groups decrease acidity. In\[\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}}\mathbf{COOH}\]and\[\mathbf{C}{{\mathbf{H}}_{\mathbf{3}}}\mathbf{C}{{\mathbf{H}}_{\mathbf{2}}}\mathbf{COOH}\]: Alkyl groups donate electrons towards\[OH\]group due to +J effect and increases the bond strength of\[CH\]bond. \[\therefore \]Acidity is decreased. In\[{{\mathbf{C}}_{\mathbf{6}}}{{\mathbf{H}}_{\mathbf{5}}}\mathbf{COOH}\]: Phenyl group attracts the electrons away from benzene ring and hence, \[OH\] bond strength decreases and therefore acidity increases. \[\mathbf{HCOOH:}\]It has neither\[+I\]or\[-I\]effect. So its acidity is not affected. \[\therefore \]\[{{C}_{6}}{{H}_{5}}COOH\]is most acidic.
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