A) \[{{N}^{3-}},{{O}^{2-}}\]
B) \[N{{a}^{+}},C{{a}^{2+}}\]
C) \[{{O}^{2-}},{{C}^{2+}}\]
D) \[{{K}^{+}},N{{a}^{+}}\]
Correct Answer: A
Solution :
Key Idea: Isoetectronic species are those which have same number of electrons. So, lets calculate and find out which pair is isoelectronic species. \[{{N}^{3-}}\]and\[O_{2}^{-}\] \[{{N}^{3-}}=7+3=10\] \[{{O}^{2-}}=8+2=10\] \[N{{a}^{+}},C{{a}^{2+}}\] \[N{{a}^{+}}=11-1=10\] \[C{{a}^{2+}}=20-2=18\] \[{{O}^{2-}},{{C}^{2-}}\] \[{{O}^{2-}}=8+2=10\] \[{{C}^{2-}}=6+2=8\] \[{{K}^{+}},N{{a}^{+}}\] \[{{K}^{+}}=9-1=18\] \[N{{a}^{+}}=11-1=10\] \[\therefore \]\[{{N}^{3-}}\]and\[{{O}^{2-}}\]are isoelectronic species.
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