A) \[C{{s}^{+}}<{{K}^{+}}<M{{g}^{2+}}<A{{l}^{3+}}\]
B) \[{{K}^{+}}<C{{s}^{+}}<M{{g}^{2+}}<A{{l}^{3+}}\]
C) \[C{{s}^{+}}<{{K}^{+}}<A{{l}^{3+}}<M{{g}^{2+}}\]
D) \[{{K}^{+}}<C{{s}^{+}}<A{{l}^{3+}}<M{{g}^{2+}}\]
Correct Answer: A
Solution :
Key Idea:\[Polari\sin g\,power\propto \frac{1}{cation\text{ }size}\] and greater the value of positive charge on the cation, smaller will be its size. \[\therefore \]\[A{{l}^{3+}}\]is smallest in size. \[\therefore \] Correct order of polarising power is \[C{{s}^{+}}<{{K}^{+}}<M{{g}^{2+}}<A{{l}^{3+}}\]
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