A) 1:9
B) 9:1
C) 3:1
D) 1:3
Correct Answer: D
Solution :
For a body mass \[m\] moving with velocity\[v\], kinetic energy is \[K=\frac{1}{2}m{{v}^{2}}\] ?(1) Also momentum \[p=\]mass \[\left( m \right)\times \] velocity \[\left( v \right)\]?(2) Squaring Eq. (2) and readjusting with terms in Eq. (1), we get \[p=\sqrt{2\,m\,K}\] Given, \[{{m}_{1}}=1\,g,{{m}_{2}}=9\,g,\,{{K}_{1}}={{K}_{2}}=K\] \[\therefore \] \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{\sqrt{2\times 1\times K}}{\sqrt{2\times 9\times K}}=\frac{1}{3}\]You need to login to perform this action.
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