A) 6 cm
B) 4 cm
C) 3 cm
D) 1.5 cm
Correct Answer: C
Solution :
Key Idea: Distance between adjacent nodes in half of wavelength. The standard equation of stationary wave is \[y=2\,a\,\sin \frac{2\pi }{\lambda }x\,\cos \frac{2\pi }{\lambda }\,ct\] ?(1) Where \[a\]is amplitude, \[\lambda \] is wavelength. Given equation is \[y=5\,\sin \frac{\pi \,x}{3}\cos \,\,40\,\pi \,t\] ?(2) Comparing Eqs. (1) and (2), we get \[\frac{2\pi }{\lambda }=\frac{\pi }{3}\] \[\Rightarrow \] \[\lambda =6\,\,cm.\] Distance between adjacent nodes \[=\frac{\lambda }{2}=\frac{6}{2}=3\,\,cm\]You need to login to perform this action.
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