A) 0.2
B) 0.4
C) 0.6
D) 0.3
Correct Answer: B
Solution :
Key Idea: \[\eta =\frac{{{T}_{1}}-{{T}_{2}}}{{{T}_{1}}}\]where, \[\eta =\]efficiency of engine \[{{T}_{1}}=\]temperature of source = 500 K \[{{T}_{2}}=\]temperature of sink = 300 K \[\eta =\frac{500-300}{500}=\frac{200}{500}=0.4\]You need to login to perform this action.
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