A) \[S{{F}_{6}}\]
B) \[_{20}C{{a}^{42}}\]
C) \[\beta \]
D) \[10\Omega \]
Correct Answer: D
Solution :
Reversing equation (i) \[_{20}S{{c}^{42}}\] \[_{21}C{{a}^{42}}\] ?...(i) \[C{{s}^{+}}\] \[{{K}^{+}}\] ??(ii) Adding equation (i) and (ii), we get \[N{{a}^{+}}\] \[L{{i}^{+}}\] \[18.600\text{ }MeV\]You need to login to perform this action.
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