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BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    The value of current through an inductance of 1 H and of negligible resistance when connected through an AC source of 200 V and 50 Hz will be:

    A)  2.001 A                

    B)  1.274 A

    C)  0.700A                

    D)  0.368 A

    Correct Answer: C

    Solution :

                                                                     Here applied emf \[{{E}_{rms}}=200V\] Frequency \[=50Hz\] Angular frequency \[=50Hz\] Inductance \[L=1\text{ }H\] The angular frequency is given by as \[=2\pi f=2\times 3.14\times 50=314\] Hence, value of current \[{{i}_{rms}}=\frac{{{E}_{rms}}}{\omega L}=\frac{220}{314\times 1}=0.700A\]


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