A) 8 J
B) 4 J
C) 16 J
D) 32 J
Correct Answer: A
Solution :
Here, initial length of spring \[{{l}_{1}}=40\text{ }mm\] Force required to stretch the spring by 1 mm = 10 N Final stretch = 40 mm The force required to stretch the string by 40 mm is given by \[=10\times 40=400N\] Average force \[F=\frac{400}{2}=200N\] Hence work done is given by = Average force \[\times \] distance \[=200\times 40=8000\text{ }Nmm\] \[=8Nm=8J\]You need to login to perform this action.
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