A) 10\[\Omega \]
B) 15\[\Omega \]
C) 5 \[\Omega \]
D) 7.5 \[\Omega \]
Correct Answer: A
Solution :
We arrange different resistance as shown, it a balanced Wheatstone bridge hence, there is no current in \[20\Omega \] resistor the equivalent circuit becomes. So, \[{{R}_{PQ}}=\frac{20\times 20}{20+20}\] \[=10\Omega \]You need to login to perform this action.
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