question_answer

In the following circuit, the resistance between points P and Q is :

A)  10\[\Omega \]                                

B)  15\[\Omega \]

C)  5 \[\Omega \]                                  

D)  7.5 \[\Omega \]

Correct Answer: A

Solution :

We arrange different resistance as shown, it a balanced Wheatstone bridge hence, there is no current in \[20\Omega \] resistor the equivalent circuit becomes. So,     \[{{R}_{PQ}}=\frac{20\times 20}{20+20}\] \[=10\Omega \]