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BVP Medical BVP Medical Solved Paper-2000

  • question_answer
    If 342 g of cane sugar  \[_{20}S{{c}^{42}}\]are dissolved in 1000 g of water, the solution will freeze at (\[_{21}C{{a}^{42}}\] for water \[C{{s}^{+}}\]):

    A)  \[{{K}^{+}}\]                     

    B)  \[N{{a}^{+}}\]

    C)  \[L{{i}^{+}}\]                    

    D)  \[18.600\text{ }MeV\]

    Correct Answer: D

    Solution :

    \[_{21}S{{c}^{42}}\] \[_{20}S{{c}^{42}}\] Thus, freezing point                 \[_{21}C{{a}^{42}}\]


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