A) \[1.40\]
B) \[2.65\]
C) \[1.85\]
D) \[2.15\]
Correct Answer: C
Solution :
For body-centered cubic (bcc) lattice radius \[(r)=\frac{\sqrt{3}}{4}a=0.433a\] Therefore, radius of \[N{{a}^{+}}=0.433\times 4.29\] \[=1.8575\]You need to login to perform this action.
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