A) 0.14\[\Omega \]
B) 0.12 \[\Omega \]
C) 1.4\[\Omega \]
D) 1.2\[\Omega \]
Correct Answer: B
Solution :
From the relation heat developed across coil is \[H=\frac{{{V}^{2}}t}{JR}cal\] or resistance of coil \[R=\frac{{{V}^{2}}t}{JH}\] Here, \[H=800\text{ }cal/sec,\text{ }V=20\text{ }volt\] So, \[R=\frac{{{(20)}^{2}}\times 1}{4.2\times 800}=0.12ohm\]You need to login to perform this action.
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