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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    A uniform chain of mass m and length f is held on a horizontal frictionless table with \[\frac{1}{3}\]rd of its length hanging vertically over the edge of the table. The work done in pulling hanging part of the chain up on the table will be:

    A) \[\frac{gml}{4}\]                                              

    B) \[\frac{gm{{l}^{2}}}{2}\]

    C) \[\frac{gml}{\sqrt{2}}\]                                

    D) \[\frac{gml}{18}\]

    Correct Answer: D

    Solution :

                                                 Initial weight of the hanging part of chain \[=\frac{mg}{3}\] Final weight of the hanging part of chain =0 So, mean weight of hanging part of chain \[\frac{\frac{mg}{3}+0}{2}=\frac{mg}{6}+0\] Work done is given by \[\frac{mg}{6}\times \frac{l}{3}=\frac{mgl}{18}\]


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