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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    A body, moving in a straight line with an initial velocity of 5 m/s and a constant acceleration, covers a distance of 30 m in the 3rd sec. How much distance will it cover in the next two seconds:

    A)  60 m

    B)  85 m

    C)  90 m                                    

    D)  100 m

    Correct Answer: C

    Solution :

                        Now, using the relation from equation of motion, \[{{s}_{t}}=u+\frac{1}{2}a(2t-1)\] \[{{s}_{t}}=u+a(t-\frac{1}{2})\] (Given, \[{{s}_{t}}=30m,\,t=3s,\,u=5m/s\]) Hence,   \[30=5+a\left( 3-\frac{1}{2} \right)\] So,   \[a=(30-5)\times \frac{2}{5}=10m/{{s}^{2}}\] Therefore,  \[{{s}_{4}}=5+10\left( 4-\frac{1}{2} \right)\] \[=5+10\times \frac{7}{2}=40m\] and  \[{{s}_{5}}=5+10\left( 5-\frac{1}{2} \right)\] \[=5+\frac{10\times 9}{2}=50m\] Hence, the distance covered after two second is \[s={{s}_{4}}+{{s}_{5}}=40+50=90m\]


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