A) 0.19
B) 1.19
C) 0.29
D) 0.019
Correct Answer: D
Solution :
Using the relation, \[\mu \gamma =\frac{\mu V+\mu R}{2}\] \[=\frac{1.524+1.514}{2}=1.519\] Now, dispersive power is given by \[\mu =\frac{\mu V-\mu R}{\mu \gamma -1}\] \[\frac{1.524-1.514}{1.519-1}=\frac{0.010}{0.519}\]You need to login to perform this action.
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