A) \[{{C}^{4-}}\]
B) \[{{N}^{3-}}\]
C) \[{{O}^{2-}}\]
D) \[M{{g}^{2+}}\]
Correct Answer: A
Solution :
These all are isoelectronic species. Greater the nuclear charge stronger is the attraction for same number of electrons and smaller is the ion. Thus, nuclear charge on \[{{C}^{4-}},{{N}^{3-}}\] and \[{{O}^{2-}}\] is 6, 7 and 8 respectively but nuclear charge on \[M{{g}^{2+}}\]is 12. Hence, \[{{C}^{4-}}\] has larger ionic radius than \[{{N}^{3-}},{{O}^{2-}}\] and \[M{{g}^{2+}}\].You need to login to perform this action.
You will be redirected in
3 sec