A) \[0.2\sqrt{3}\]gauss
B) 0.8 gauss
C) 0.2 gauss
D) \[\frac{0.8}{\sqrt{3}}\] gauss
Correct Answer: B
Solution :
(Here, \[H=0.4\]gauss, \[\theta ={{60}^{o}}\]) Using the relation, \[H={{B}_{e}}\cos \theta \] or \[{{B}_{e}}=\frac{H}{\cos \theta }\] so, \[{{B}_{e}}=\frac{0.4}{\cos {{60}^{o}}}=0.8gauss\]You need to login to perform this action.
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