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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    Decreasing order of s-character is \[sp,s{{p}^{2}},s{{p}^{3}}\]-hybrid orbitals:

    A)  \[s{{p}^{3}}>s{{p}^{2}}>sp\]

    B)  \[sp>s{{p}^{2}}>s{{p}^{3}}\]

    C)  \[s{{p}^{3}}>sp>s{{p}^{2}}\]

    D)  \[s{{p}^{2}}>sp>s{{p}^{3}}\]

    Correct Answer: B

    Solution :

                    s-character in sp-hybrid orbital = 50% s-character in sp hybrid orbital = 33% s-character in sp hybrid orbital =25% Decreasing order \[sp>s{{p}^{2}}>s{{p}^{3}}\]


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